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9709 · 2.1

Algebra — common mistakes

Common exam mistakes on 9709 Algebra. Learn what loses marks, then practise the topic with Examiner’s Ink.

Exam tip 1

When finding the constants (A, B, C...), substituting strategic values of xx is often much faster than equating coefficients. For a term Ax−a\frac{A}{x-a}, substituting x=ax=a into the cross-multiplied equation will quickly isolate AA. Also, always check if the fraction is improper (degree of numerator ≥\ge degree of denominator) before you start. If it is, you must perform polynomial division first.

Exam tip 2

A very common question asks for the expansion and the range of values for which it is valid. Do not forget to state the validity range, e.g., ∣x∣<12|x| < \frac{1}{2}. This is an easy mark to gain and an easy one to lose. Be careful with signs, especially when nn is negative.

When solving $|f(x)| = |g(x)|$, is squaring both sides always the best method?

Squaring is a very reliable method because it correctly removes the modulus signs. However, it can lead to a more complicated polynomial to solve. The alternative method, setting f(x)=g(x)f(x) = g(x) and f(x)=−g(x)f(x) = -g(x), can be quicker but requires careful management of signs and brackets. Both methods are valid; choose the one you are most comfortable and accurate with.

What's the difference between the Remainder Theorem and the Factor Theorem?

The Factor Theorem is simply a special case of the Remainder Theorem. The Remainder Theorem tells you the remainder when you divide a polynomial P(x)P(x) by (x−a)(x-a) is P(a)P(a). The Factor Theorem states that if this remainder P(a)P(a) happens to be 0, then (x−a)(x-a) must be a factor.

Why do we learn partial fractions? What are they used for?

The primary application of partial fractions in A-Level Mathematics is in integration (which you will study in depth). It is much easier to integrate a sum of simple fractions (like 2x−1+3x+2\frac{2}{x-1} + \frac{3}{x+2}) than it is to integrate the single complex fraction they came from. We also use them in binomial expansions.

For the binomial expansion, what if the power is a positive integer?

If the power nn is a positive integer, the expansion formula still works, but it will terminate. The term with (n−n)(n-n) in the numerator will become zero, so all subsequent terms are zero. This gives a finite series, the same as the one you learned in P1 using combinations (nCr).